6z^2=24z

Solution for 6z^2=24z equation:

6z^2=24z

We move all terms to the left:

6z^2-(24z)=0

a = 6; b = -24; c = 0;
Δ = b2-4ac
Δ = -242-4·6·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-24}{2*6}=\frac{0}{12}
=0
$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+24}{2*6}=\frac{48}{12}
=4
$